A thin circular wire carrying a current $I$ has a magnetic moment $M$. The shape of the wire is changed to a square and it carries the same current. It will have a magnetic moment
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$M=I\left(\pi r^{2}\right)$

$\pi=\frac{\mathrm{L}}{2 \pi}$

$\mathrm{M}=\mathrm{I}\left(\frac{\pi \times \mathrm{L}^{2}}{4 \pi^{2}}\right)=\frac{\mathrm{IL}^{2}}{4 \pi}$

$\mathrm{m}^{\prime}=\frac{\mathrm{IL}^{2}}{16}$

$\mathrm{m}^{\prime}=\frac{4 \pi \mathrm{M}}{16}=\frac{\pi \mathrm{M}}{4}$

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