$\pi=\frac{\mathrm{L}}{2 \pi}$
$\mathrm{M}=\mathrm{I}\left(\frac{\pi \times \mathrm{L}^{2}}{4 \pi^{2}}\right)=\frac{\mathrm{IL}^{2}}{4 \pi}$
$\mathrm{m}^{\prime}=\frac{\mathrm{IL}^{2}}{16}$
$\mathrm{m}^{\prime}=\frac{4 \pi \mathrm{M}}{16}=\frac{\pi \mathrm{M}}{4}$

$(i)$ an equilateral triangle of side $'a'.$
$(ii)$ a square of side $'a'.$
The magnetic dipole moments of the coil in each case respectively are:

Statement $(I)$: When an object is placed at the centre of curvature of a concave lens, image is formed at the centre of curvature of the lens on the other side.
Statement $(II)$: Concave lens always forms a virtual and erect image.
In the light of the above statements, choose the correct answer from the options given below: