An electron is accelerated by a potential difference of $12000\, volts$. It then enters a uniform magnetic field of ${10^{ - 3}}\,T$ applied perpendicular to the path of electron. Find the radius of path. Given mass of electron $ = 9 \times {10^{ - 31}}\,kg$ and charge on electron $ = 1.6 \times {10^{ - 19}}\,C$
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(b) $r = \frac{{\sqrt {2mK} }}{{qB}} = \frac{1}{B}\sqrt {\frac{{2mV}}{q}} $
$ = \frac{1}{{{{10}^{ - 3}}}}\sqrt {\frac{{2 \times 9 \times {{10}^{ - 31}} \times 12000}}{{1.6 \times {{10}^{ - 19}}}}} $ = $0.367\, m = 36.7\, cm$
$ = \frac{1}{{{{10}^{ - 3}}}}\sqrt {\frac{{2 \times 9 \times {{10}^{ - 31}} \times 12000}}{{1.6 \times {{10}^{ - 19}}}}} $ = $0.367\, m = 36.7\, cm$
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