A thin flexible wire of length $\mathrm{L}$ is connected to two adjacent fixed points and carries a current $\mathrm{I}$ in the clockwise direction, as shown in the figure. When the system is put in a uniform magnetic field of strength $B$ going into the plane of the paper, the wire takes the shape of a circle. The tension in the wire is
A$IBL$
B$\frac{\mathrm{IBL}}{\pi}$
C$\frac{\mathrm{IBL}}{2 \pi}$
D$\frac{\mathrm{IBL}}{4 \pi}$
IIT 2010, Advanced
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C$\frac{\mathrm{IBL}}{2 \pi}$
c $ 2 \mathrm{~T} \sin \frac{\mathrm{d} \theta}{2}=\mathrm{BiRd} \theta $
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