
$\frac{\mathrm{dF}}{\mathrm{dy}}=0$
$-\frac{\eta}{y^{2}}+\frac{4 \eta}{(d-y)^{2}}=0$
$\frac{\mathrm{d}-\mathrm{y}}{\mathrm{y}}=2$
$y=\frac{d}{3}, \Rightarrow d_{1}=\frac{d}{3}, d_{2}=\frac{2 d}{3}$
$\frac{\mathrm{d}_{2}}{\mathrm{d}_{1}}=2$
(given atmospheric pressure $P_{A}=1.01 \times 10^{5}\,Pa$, density of water $\rho_{ w }=1000\,kg / m ^{3}$ and gravitational acceleration $g=10\,m / s ^{2}$ )


(The coefficient of viscosity of water is $9.8 \times 10^{-6}$ $\left.\mathrm{N} \mathrm{s} / \mathrm{m}^2\right)$