MCQ
A thin wire of length $L$ and uniform linear mass density $\lambda$ is bent into a circular ring. The $\mathrm{MI}$ of the ring about a tangential axis in its plane is
  • A
    $\frac{3 \lambda L^2}{8 \pi^2}$
  • B
    $\frac{8 \pi^2}{3 \lambda L^3}$
  • $\frac{3 \lambda L^3}{8 \pi^2}$
  • D
    $\frac{8 \pi^2}{3 \lambda L^2}$,

Answer

Correct option: C.
$\frac{3 \lambda L^3}{8 \pi^2}$
$\frac{3 \lambda L^3}{8 \pi^2}$

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