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5. Magnetism and matter — Physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 SciencePhysics5. Magnetism and matter1 Mark
MCQ
A toroid having average diameter $2.5\,m ,$ number $A$ turns $400,$ current $=2 \,A$ and magnetic field has $10, T$ what will be induced magnetic field (in $amp/m)$
  • A
    $\frac{10^{5}}{4 \pi}$
  • ✓
    $\frac{10^{8}}{4 \pi}$
  • C
    $\frac{10^{8}}{2 \pi}$
  • D
    $\frac{10^{2}}{2 \pi}$
✓

Answer

Correct option: B.
$\frac{10^{8}}{4 \pi}$
b
The expression to calculate the induced magnetic field is given as,

$B =\mu_{0}( H + I )$

$=\mu_{0}\left(\frac{ N }{2 \pi r } \times i + I \right)$

Substitute the values.

$10=\mu_{0}\left(\frac{ N }{2 \pi r } \times i + I \right)$

$I=\frac{10}{4 \pi \times 10^{-7}}-\frac{400 \times 2 \times 2}{2 \pi \times 2.5}$

$=\frac{10^{8}}{4 \pi}$

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