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Motion — Science STD 9 — Question

Gujarat BoardEnglish MediumSTD 9ScienceMotion2 Marks
Question
A train starting from stationary position and moving with uniform acceleration attains a speed of $36km$ per hour in $10$ minutes. Find its acceleration.
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Answer

Initial velocity, $u = 0m/s$
Final velocity, $v = 36km/h = 10m/s$
Time, $t = 10min = 10 x 60 = 600 sec$
Acceleration, $a = ?$
Acceleration $=\frac{\text{Final velocity-Initial velocity}}{\text{time taken}}$
So, $\text{a}=\frac{\text{v-u}}{\text{t}}$
$=\frac{10-0}{600}=\frac{10}{600}\text{m/s}^2$
$=\frac{1}{60}\text{m/s}^2-0.16\text{m/s}^2$

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