$\beta=\frac{\alpha}{1-\alpha}=\frac{0.96}{1-0.96}=24$
The collector current $\mathrm{I}_{\mathrm{C}}$ is given by
$\mathrm{I}_{\mathrm{C}}=\frac{\mathrm{V}_{\mathrm{C}}}{\mathrm{R}}=\frac{0.5}{800}=0.625 \times 10^{-3} \mathrm{A}$
Further $\mathrm{I}_{\mathrm{B}}=\frac{\mathrm{I}_{\mathrm{C}}}{\beta}=\frac{0.625 \times 10^{-3}}{24}$
$=26 \times 10^{-6} \mathrm{A}=26\, \mu \mathrm{A}$
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$\mathrm{E}_{\mathrm{y}}=\left(200\ \mathrm{Vm}^{-1}\right) \sin \left[1.5 \times 10^7 \mathrm{t}-0.05\ \mathrm{x}\right] \text {; }$
The intensity of the wave is :(Use $\in_0=8.85 \times 10^{-12} \mathrm{C}^2 \mathrm{~N}^{-1} \mathrm{~m}^{-2}$ )
