MCQ
A transverse progressive wave on a stretched string has a velocity of $10\,m{s^{ - 1}}$ and a frequency of $100 Hz.$ The phase difference between two particles of the string which are $2.5 cm$ apart will be
  • A
    $\frac{\pi }{8}$
  • B
    $\frac{\pi }{4}$
  • C
    $\frac{{3\pi }}{8}$
  • $\frac{\pi }{2}$

Answer

Correct option: D.
$\frac{\pi }{2}$
d
(d) $v = n\lambda \Rightarrow \lambda = 10\,\,cm$

Phase difference $\frac{{2\pi }}{\lambda } \times $ Path difference

=$\frac{{2\pi }}{{10}} \times 2.5$= $\frac{\pi }{2}$

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