MCQ
A transverse wave is given by $y = A\sin 2\pi \left( {\frac{t}{T} - \frac{x}{\lambda }} \right)$. The maximum particle velocity is equal to $4$ times the wave velocity when
- A$\lambda = 2\pi A$
- ✓$\lambda = \frac{1}{2}\pi A$
- C$\lambda = \pi A$
- D$\lambda = \frac{1}{4}\pi A$
