A transverse wave is represented by $y=2 \sin$ $(\omega t - kx ) cm$. The value of wavelength (in $cm$ ) for which the wave velocity becomes equal to the maximum particle velocity, will be.
JEE MAIN 2022, Medium
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$y=2 \sin (\omega t-k x)$

Maximum particle velocity $= A \omega$

Wave velocity $=\frac{\omega}{ k }$

$\frac{\omega}{ k }= A \omega$

$k =\frac{1}{ A }=\frac{2 \pi}{\lambda}$

$\lambda =2 \pi A$

$=4 \pi\,cm$

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