Question
A tree is broken by the wind but does not separate. If the point from where it breaks is 9m above the ground and its top touches the ground at a distance of 12m from its foot, find out the total height of the tree before it broke.

Answer


Let $A B$ be the tree which broke at $D$ and its top $A$ touches the ground at $C$.
Their $B D=5 m$ and $B C=12 m$
Let $A D=x m$, then $C D=x m$
Now, in right $\triangle ABC$,
$C D^2=B D^2+B C^2$ (By Pythagoras Theorom)
$C D^2=(9)^2+(12)^2$
$\Rightarrow C D^2=81+144$
$\Rightarrow C D^2=225$
$\Rightarrow C D^2=(15)^2$
$CD =15 m$
$AD = x =15 m$
Height of the tree $A B=A D+B D=15+9=24 m$.

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