MCQ
A triangular corner is cut from a rectangular piece of paper and the resulting pentagon has sides $5,6,8,9, 12$ in some order. The ratio of the area of the pentagon to the area of the rectangle is
  • A
    $\frac{11}{18}$
  • B
    $\frac{13}{18}$
  • C
    $\frac{15}{18}$
  • $\frac{17}{18}$

Answer

Correct option: D.
$\frac{17}{18}$
d
(d)

We have,

A rectangular corner is cut form a rectangular piece of paper.

Area of rectangle

$\quad=12 \times 9=108 \text { sq units }$

$\text { Area of pentagon }$

$\qquad \quad=\text { Area of rectangle }-\text { Area of triangle }$

$\quad=108-6=102$

$\therefore \text { Ratio }=\frac{102}{108}=\frac{17}{18}$

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