Question
A tube well pump throws up 2400 kg of water in every mintue. If the speed of water coming out is $3 m / s$ then find the power of the pump. If the pump runs for 5 hours then find the value of work done by the pump.
✓
Answer
Given,
$\begin{aligned}
m & =2400 kg \\
t & =1 minute=60 \text { seconds } \\
v & =3 m / s \\
\therefore \text { Power of pump } & =\frac{1}{2} \frac{m v^2}{t} \\
& =\frac{2400 \times 3 \times 3}{2 \times 60}=180 \text { watt }
\end{aligned}$
If the pump runs for 5 hours then work done,
$\begin{aligned}
W & =P \times t \\
& =180 \times 5 \times 60 \times 60 \\
& =18 \times 5 \times 6 \times 6 \times 10^3 J \\
& =3240 \times 10^3 \\
or
W & =3.24 \times 10^6 J \quad Ans.
\end{aligned}$
$\begin{aligned}
m & =2400 kg \\
t & =1 minute=60 \text { seconds } \\
v & =3 m / s \\
\therefore \text { Power of pump } & =\frac{1}{2} \frac{m v^2}{t} \\
& =\frac{2400 \times 3 \times 3}{2 \times 60}=180 \text { watt }
\end{aligned}$
If the pump runs for 5 hours then work done,
$\begin{aligned}
W & =P \times t \\
& =180 \times 5 \times 60 \times 60 \\
& =18 \times 5 \times 6 \times 6 \times 10^3 J \\
& =3240 \times 10^3 \\
or
W & =3.24 \times 10^6 J \quad Ans.
\end{aligned}$
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