Question
A U-shaped wire is dipped in a soap solution, and removed. The thin soap film formed between the wire and the light slider supports a weight of 1.5 × 10–2N (which includes the small weight of the slider). The length of the slider is 30cm. What is the surface tension of the film?

Answer

The weight that the soap film supports, W = 1.5 × 10-2N

Length of the slider, l = 30cm = 0.3m

A soap film has two free surfaces.

$\therefore$ Total length = 2l = 2 × 0.3 = 0.6m

Surface tension, $\text{S}=\frac{\text{Force of Weight}}{2\text{l}}$

$= 1.5 \times\frac{10^{-2}}{0.6}=  2.5\times10-2\text{N/m}$

Therefore, the surface tension of the film is 2.5 × 10-2N m-1.

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