Question
A uniform electric field exists between two charged plates as shown in the fig. What should be the work done in moving a charge $q$ along the closed rectangular path $\text{ABCD}$?

Answer

Work done in an electric field is independent of the path and depends only on the initial and final positions.
Here initial and final points are coincident,
Work $= q \times (V_{final} - V_{initial})$
$= q \ (VA - VA)$
So, net work done is zero.

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