Question
A uniform magnetic field of $0.20 \times 10^{-3} \mathrm{~T}$ exists in the space. Find the change in the magnetic scalar potential as one moves through 50 cm along the field.
✓
Answer
$\text{B}=-\frac{\text{dv}}{\text{dt}}\Rightarrow\text{dv}=-\text{B dt}$$=-0.2\times10^{-3}\times0.5=-0.1\times10^{-3}\text{T-m}$
Since the sigh is-ve therefore potential decreases.
Since the sigh is-ve therefore potential decreases.
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