A uniform magnetic field of $0.3\; T$ is established along the positive $Z$ -direction. A rectangular loop in $XY$ plane of sides $10 \;cm$ and $5 \;cm$ carries a current of $I =12\; A$ as shown. The torque on the loop is
A$-1.8 \times 10^{-2}$$\hat j\;Nm$
B$0$
C$-1.8 \times 10^{-2}$ $\hat i\;Nm$
D$+1.8 \times 10^{-2}$ $\hat i\;Nm$
NEET 2017, Medium
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B$0$
b $\vec{\tau}= NIA \times \overline{ B }$
Here $\overrightarrow{ A } \| \overrightarrow{ B }$
$\theta=0$
$\vec{\tau}= NIAB \sin \theta$
$\vec{\tau}=0$
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