A uniform magnetic field of $3000\,G$ is established in the positive $z-$ direction. A rectangular loop of side $10\,cm$ and $5\,cm$ carries a current of $12\,A.$ What is the magnitude of placed as shown torque on the loop is
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${\text{Z}} = {\text{MB}}\sin \theta $
${\text{M}} = {\text{NIA}}$
$ = 10 \times 5 \times 12 \times {10^{ - 4}}$
$ = 6 \times {10^{ - 2}}\,{\text{A}} - {{\text{m}}^2},\quad {\text{B}} = 0.3\,{\text{T}}$
as $\theta=0$
$Z=0$
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