b
$I =2\,A$
$\Delta V =3.4\,V$
Using Ohm's Law
$R =\frac{3.4}{2}=1.7 \Omega$
$1.7=\frac{\rho L }{ A }$
$L =\frac{1.7( A )}{\rho}$
$M =(\text { density volume })$
$Volume =\frac{8.92 \times 10^{-3}}{8.92 \times 10^3}=10^{-6}$
$L ^2=\frac{1.7}{\rho}\left(10^{-6}\right)=\frac{1.7}{1.7} \times 10^2$
$L =10\,m$