A uniform narrow $1.95\,\, m$ long pipe is open at both ends. It resonates at two successive harmonic of frequency $275\,\, Hz$ and $330 \,Hz.$The speed of sound in the tube is ...... $m/s$
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$\frac{n}{2 \times 1.95} \times v=275$
$\frac{(n+1)}{2 \times 1.95} \times v=330$
$\frac{v}{2 \times 1.95}=55$
$\mathrm{v}=55 \times 3.9=214.5 \mathrm{m} / \mathrm{s}$
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