MCQ
A uniform vertical electric field $E$ is established in the space between two large parallel  plates. A small conducting sphere of mass $m$ is suspended in the field from a string of  length $L$. If the sphere is given $a + q$ charge and the lower plate is charged positvely, the period of oscillation of this pendulum is :- 
  • A
    ${2\pi }\sqrt[]{{\frac{L}{g}}}$
  • B
    ${2\pi }\sqrt[]{{\frac{L}{{g + (qE/m)}}}}$
  • ${2\pi }\sqrt[]{{\frac{L}{{g - (qE/m)}}}}$
  • D
    ${2\pi }\sqrt[]{{\frac{L}{{{{\left[ {{g^2} - {{(qE/m)}^2}} \right]}^{\frac{1}{2}}}}}}}$

Answer

Correct option: C.
${2\pi }\sqrt[]{{\frac{L}{{g - (qE/m)}}}}$
c
The equation of motion of sphere, $m a=m g-q E \Rightarrow a=g-\frac{q E}{m}$

Thus the effective acceleration of sphere oscillation will become$:$ $g^{\prime}=a=g-\frac{q E}{m}$

Time period, $T=2 \pi \sqrt{\frac{L}{g^{\prime}}}=2 \pi \sqrt{\frac{L}{g-\frac{q E}{m}}}$

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