$\left(\alpha_{\text {iron }}=1.2 \times 10^{-5} K ^{-1}\right.$ and $\left.\alpha_{\text {brass }}=1.8 \times 10^{-5} K ^{-1}\right)$.
- A$59$
- B$6$
- ✓$60$
- D$600$
$\left(\alpha_{\text {iron }}=1.2 \times 10^{-5} K ^{-1}\right.$ and $\left.\alpha_{\text {brass }}=1.8 \times 10^{-5} K ^{-1}\right)$.
$\alpha_{ B } \ell_{ B }=\ell_{ i } \alpha_{ i }$
$1.8 \times 10^{-5} \times 40=\ell_{ i } \times 1.2 \times 10^{-5}$
$\ell_{ i }=\frac{1.8 \times 10^{-5} \times 40}{1.2 \times 10^{-5}}=\frac{3 \times 40}{2}=60$ $\ell_{ i }=60\,cm$
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$1.$ Which of the following statement regarding the angular speed about the istantaneous axis (passing through the centre of mass) is correct?
$(A)$ It is $\sqrt{2} \omega$ for boht the cases
$(B)$ it is $\omega$ for case $(a)$; and $\frac{w}{\sqrt{2}}$ for case $(b)$.
$(C)$ It is $\omega$ for case $(a)$; and $\sqrt{2} \omega$ for case $(b)$.
$(D)$ It is $\omega$ for both the cases
$2.$ Which of the following statements about the instantaneous axis (passing through the centre of mass) is correct?
$(A)$ It is vertical for both the cases $(a)$ and $(b)$.
$(B)$ It is verticle for case $(a)$; and is at $45^{\circ}$ to the $x-z$ plane and lies in the plane of the disc for case $(b)$
$(C)$ It is horizontal ofr case $(a)$; and is at $45^{\circ}$ to the $x - z$ plane and is normal to the plane of the disc for case $(b)$.
$(D)$ It is vertical of case $(a)$; and is at $45^{\circ}$ to the $x - z$ plane and is normal to the plane of the disc for case $(b)$.
Give the answer question $1$ and $2.$