STD 12 - 10. vector algebra — JEE STD 11 Science — Question

We have,

$a =3 i -4 k$ and $b =5 j +12 k$

We know that,

angle bisector of vector $a$ and $b$

$=\lambda\left[\frac{ a }{| a |}+\frac{ b }{| b |}\right]$

$\therefore \lambda\left[\frac{3 \hat{ i }-4 \hat{ k }}{5}+\frac{5 \hat{ j }+12 \hat{ k }}{13}\right]$

$=\lambda\left[\frac{39 \hat{ i }-52 \hat{ k }+25 \hat{ j }+60 \hat{ k }}{65}\right]$

$=\lambda[39 \hat{ i }+2 \hat{ j}+8 \hat{ k }]$