A vertical hanging bar of length $l$ and mass $m$ per unit length carries a load of mass $M$ at lower end, its upper end is clamped to a rigid support. The tensile stress a distance $x$ from support is $(A \rightarrow$ area of cross-section of bar)
Medium
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(b)
Tensile stress $=\frac{\text { Tension at point }}{\text { Area }}$
Tension at distance $x$ from top would be the amount of force acting due to all the weight below it
$=$ Mass per unit length of rod $\times$ length of rod $+M g$ $=m \times(I-x) g+M g$
So Tensile stress $=\frac{m(I-x) g+M g}{A}$
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