A vertical spring with constant 200N/ m has a light platform on i… - Vidyadip

Question

A vertical spring with constant $200N/ m$ has a light platform on its top. When a $500g$ mass is kept on the platform spring compresses $2.5cm$. Mass is now pushed down $7.50cm$ further and released. How far above later position will the mass fly? $(g = 10ms^{-2})$.

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Answer

When the external force is removed after the push, the mass gets detached when spring obtain its natural length and say, mass m rises h height from the pushed position.

Loss in Potential energy of spring = Gain in gravitational potential energy. $\frac{1}{2}\text{k}[\text{x}^2]=\text{mgh}$ $\frac{1}{2}\times200[0.1]^2$ = 0.5 × 10 × h 1 = 5h ⇒ h = 0.2m

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