MCQ
A vessel at $1000\,K$ contains $CO_2$ with a pressure of $0.5\, atm.$ Some of the $CO_2$ is converted into $CO$ on the addition of graphite. If the total pressure at equilibrium is $0.8\, atm,$ the value of $K$ is .....$atm$
  • $1.8$
  • B
    $3$
  • C
    $0.3$
  • D
    $0.18$

Answer

Correct option: A.
$1.8$
a
$C O_{2}+C_{(\text {grapnite})} \rightleftharpoons 2 C O$

$P_{\text {initial}} 0.5 \;\,a t m$        $0$

$P_{\text {final}}(0.5-x)\;\,atm$        $ 2 x\; \,atm$

Total $P$ at equilibrium

$=0.5-x+2 x=0.5+x$ atm

$0.8=0.5+x$

$\therefore x=0.8-0.5=0.3\, a t m$

Now $k_{p}=\left(P_{C O}\right)^{2} / P_{C O_{2}}$

$=\frac{(2 \times 0.3)^{2}}{(0.5-0.3)}=\frac{(0.6)^{2}}{(0.2)}$

$=1.8 \mathrm{\,atm}$

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