A vessel contain a liquid has a constant acceleration $19.6 \,m / s ^2$ in horizontal direction. The free surface of water get sloped with horizontal at angle ..........
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(d)
$\tan \theta=\frac{a}{g}=\frac{19.6}{9.8}=2$
$\tan \theta=2$
$\Rightarrow \sin \theta=\frac{2}{\sqrt{5}} \Rightarrow \theta=\sin ^{-1}\left[\frac{2}{\sqrt{5}}\right]$
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