MCQ
A vessel is partitioned in two equal halves by a fixed diathermic separator. Two different ideal gases are filled in left $(L)$ and right $(R)$ halves. The rms speed of the molecules in $L$ part is equal to the mean speed of molecules in the $R$ part. Then the ratio of the mass of a molecule in $L$ part to that of a molecule in $R$ part is
  • A
    $\sqrt {\frac{3}{2}} $
  • B
    $\sqrt {\pi /4} $
  • C
    $\sqrt {2/3} $
  • $3\pi /8$

Answer

Correct option: D.
$3\pi /8$
d
The left side of the container has a gas, let having molecular wt. $M_{1}$ Right part has Mol. wt $=M_{2}$

Temperature of both left and right chambers are equal as the separating wall is diathermic

$\sqrt{\frac{3 R T}{M_{1}}}=\sqrt{\frac{8 R T}{\pi M_{2}}} \Rightarrow \frac{3 R T}{M_{1}}=\frac{8 R T}{\pi M_{2}} \Rightarrow \frac{M_{1}}{\pi M_{2}}$

$= \frac{3}{8} \Rightarrow \frac{M_{1}}{ M _{2}}=\frac{3 \pi}{8}=1.1775 \approx 1.18$

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