Aboth the holes will fall at the same spot
a
Velocity of water from hole
$A = {v_1} = \sqrt {2gh} $
Velocity of water from hole $B$
$ = {v_2} = \sqrt {2g\left( {{H_0} - h} \right)} $
Time of reching the ground from hole $B$
$ = {t_1} = \sqrt {2\left( {{H_0} - h} \right)/g} $
Time of reaching the ground from hole $A$
$ = {t_2} = \sqrt {2h/g} $