Question
A wave pulse passing on a string with a speed of 40cm/s in the negative x-direction has its maximum at x = 0 at t = 0. Where will this maximum be located at t = 5s?
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Answer
v = 40cm/sec
As velocity of a wave is constant location of maximum after 5sec
= 40 × 5 = 200cm along negative x-axis.
As velocity of a wave is constant location of maximum after 5sec
= 40 × 5 = 200cm along negative x-axis.
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