$y=A \sin (k x-\omega t)$
where
$A=$ Amplitude of the wave
$k=$ angular wave number
$\omega=$angular frequency of the wave
Given: $A=1 \mathrm{m}, \lambda=2 \pi \mathrm{m}, \quad v=\frac{1}{\pi} \mathrm{Hz}$
As $\quad k=\frac{2 \pi}{\lambda}=\frac{2 \pi}{2 \pi}=1$
$\omega=2 \pi v=2 \pi \times \frac{1}{\pi}=2$
$\therefore$ The equation of the given wave is
$y=1 \sin (1 x-2 t)=\sin (x-2 t)$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Colum $I$ | Colum $II$ |
| $(A)$ Displacement | $(p)$ $8 \sin 2$ |
| $(B)$ Distance | $(q)$ $4$ |
| $(C)$ Average velocity | $(r)$ $2 \sin 2$ |
| $(D)$ Average acceleration | $(s)$ $4 \sin 2$ |
