$y=A \sin (k x-\omega t)$

where

$A=$ Amplitude of the wave

$k=$ angular wave number

$\omega=$angular frequency of the wave

Given: $A=1 \mathrm{m}, \lambda=2 \pi \mathrm{m}, \quad v=\frac{1}{\pi} \mathrm{Hz}$

As $\quad k=\frac{2 \pi}{\lambda}=\frac{2 \pi}{2 \pi}=1$

$\omega=2 \pi v=2 \pi \times \frac{1}{\pi}=2$

$\therefore$ The equation of the given wave is

$y=1 \sin (1 x-2 t)=\sin (x-2 t)$