MCQ
A weak acid $HX$ has the dissociation constant $1 \times 10^{-5}\,M$ . It forms a salt $NaX$ on reaction with alkali. The percentage hydrolysis of $0.1\,M$ solution of $NaX$ is ............... $\%$
- A$0.0001$
- ✓$0.01$
- C$0.1$
- D$0.15$
So, hydrolysis of $\mathrm{NaX}$ will be
$h=\sqrt{\frac{K_{w}}{K_{a} \times C}}=\sqrt{\frac{10^{-14}}{10^{-5} \times 0.1}}=10^{-4}$
Therefore, $\%$ hydrolysis will be $=10^{-4} \times 100=0.01 \%$
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