MCQ
A wheel has angular acceleration of $3 .0\, rad/sec^2$ and an initial angular speed of $2.00\, rad/sec.$ In a time of $2\, sec$ it has rotated through an angle (in radian) of
- ✓$10$
- B$12$
- C$4$
- D$6$
${\omega _i} = 2\,rad/\sec $
Time $t = 2 \;sec$
Using, $\theta = {\omega _i}t + \frac{1}{2}\alpha {t^2}$
$\therefore \,\theta = 2 \times 2 + \frac{1}{2} \times 3 \times 4 $$= 4 + 6 = 10\,radian.$
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$(1)$ The radial acceleration of the rod's center of mass will be $\frac{3 g }{4}$
$(2)$ The angular acceleration of the rod will be $\frac{2 g }{ L }$
$(3)$ The angular speed of the rod will be $\sqrt{\frac{3 g}{2 L}}$
$(4)$ The normal reaction force from the floor on the rod will be $\frac{ Mg }{16}$
