MCQ
$(A)$ will be
- A$\begin{array}{*{20}{c}}
{OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{{C_6}{H_5}CH - C{H_2}CHO}
\end{array}$ - ✓$C_6H_5CH = CH -CHO$
- C$C_6H_5CH_2CH_2CHO$
- DBoth $(b)$ and $(c)$
✓
Answer
Correct option: B.
$C_6H_5CH = CH -CHO$
b
Aldol formed in aromatic aldehydes itself loses water molecule without heating because double bond formed is more stable due to conjugation with benzene ring. $C_6H_5CH=CHCHO$ is commonly known as cinnamaldehyde
Aldol formed in aromatic aldehydes itself loses water molecule without heating because double bond formed is more stable due to conjugation with benzene ring. $C_6H_5CH=CHCHO$ is commonly known as cinnamaldehyde
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