A wire elongates by $l$ $mm$ when a load $W$ is hanged from it. If the wire goes over a pulley and two weights $W$ each are hung at the two ends, the elongation of the wire will be (in $mm$)
AIEEE 2006, Medium
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Case $(i)$
At equilibrium, $T=W$
$Y=\frac{W / A}{l / L}$ $...(1)$
Case $(ii)$ At equilibrium $T=W$
$\therefore Y=\frac{W / A}{l / 2} \Rightarrow Y=\frac{W / A}{l / L}$
Elongation is the same.
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