$\frac{1}{\text{R}_{\text{eq}}}=\frac{3}{\text{R}_{1}}+\frac{3}{\text{R}_{2}}+\frac{3}{\text{R}_{3}}$
$\frac{1}{\text{R}_{\text{eq}}}=\frac{1}{\frac{\text{R}}{3}}+\frac{1}{\frac{\text{R}}{3}}+\frac{1}{\frac{\text{R}}{3}}$
$\frac{1}{\text{R}_{\text{eq}}}=\frac{3}{\text{R}}+\frac{3}{\text{R}}+\frac{3}{\text{R}}$
$\frac{1}{\text{R}_{\text{eq}}}=\frac{9}{\text{R}}$
$\frac{1}{\text{R}_{\text{eq}}}=\frac{\text{R}}{9}\Omega $
The resistivity is dependent on the nature of the material.
Hence, there will be no change in the reisitivity of the wire.
$\text{V}=\text{I}\times\text{R}$
$\text{I}=\frac{\text{V}}{\text{R}}=\frac{\text{V}}{\frac{\text{R}}{9}}=\frac{9\text{V}}{\text{R}}$
$\therefore\text{I}=9\times\text{I}$
Thus, the current will increase 9 times than the previous current.
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