A wire of area of cross-section ${10^{ - 6}}{m^2}$ is increased in length by $0.1\%$. The tension produced is $1000 N$. The Young's modulus of wire is
Medium
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(a) $Y = \frac{{FL}}{{Al}} = \frac{{1000 \times 100}}{{{{10}^{ - 6}} \times 0.1}} = {10^{12}}N/{m^2}$
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