MCQ
A wire of length $L$ is hanging from a fixed support. The length changes to $L _{1}$ and $L _{2}$ when masses $1 \,kg$ and $2 \,kg$ are suspended respectively from its free end. Then the value of $L$ is equal to ..................
  • A
    $\sqrt{ L _{1} L _{2}}$
  • B
    $\frac{ L _{1}+ L _{2}}{2}$
  • $2 L _{1}- L _{2}$
  • D
    $3 L_{1}-2 L_{2}$

Answer

Correct option: C.
$2 L _{1}- L _{2}$
c
By Hooke's Law

so $F \alpha \Delta L$

$\frac{ F _{1}}{ F _{2}}=\frac{\Delta L _{1}}{\Delta L _{2}}$

$\frac{10}{20}=\frac{\left(L_{1}-L\right)}{\left(L_{2}-L\right)}$

$L =2 L _{1}- L _{2}$

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