MCQ
A zener diode is specified as having a breakdown voltage of $9.1 \;V$, with a maximum power dissipation of $364 \;mW$. What is the maximum current ($mA$) the diode can handle?
- A$28$
- B$20 $
- C$35 $
- ✓$40$
✓
Answer
Correct option: D.
$40$
d
The maximum permissible current is
The maximum permissible current is
$I_{Z_{\max }}=\frac{P}{V_Z}$
$=\frac{364 \times 10^{-3}}{9.1}$
$=40 mA$
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