Question
$\alpha^2+\beta^2$

Answer

$y^2-2 y-7=0 $
$ \alpha+\beta=2 \text { and } \alpha \beta=-7 $
$ \text { (1). }(\alpha+\beta)^2=\alpha^2+\beta^2+2 \alpha \beta$
$ \Rightarrow(2)^2=\alpha^2+\beta^2+2(-7) $
$ \Rightarrow 4+14=\alpha^2+\beta^2$
$ \Rightarrow \alpha^2+\beta^2=18$

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