$CH_3CH=CHCH_2CHBrCH_3$
Number of optical isomers $=2^{n}$
where, $n=$ number of asymmetric carbon atoms
$2^{1}=2$
Number of geometrical isomers $=2^{n}$ where, $n=$ number of double bonds $=2^{1}=2$
Hence, total number of stereoisomers = Total optical isomers $4 -$ Total geometrical isomers
$=2+2=4$
$CH_3CH=CHCH_2CHBrCH_3$
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