
Now, the lowest set of locant rule is considered.
Number $1$ is given to $- CN$ group, $- Br$ will be at the $2^{\text {nd }}$ position and $- OH$ will be at the $5^{\text {th }}$ position.
So, the name is $2$-bromo-$5$-hydroxybenzonitrile.
$(i)$ $C{H_3}C{H_2}C{H_2}C{H_3}$
$(ii)$ $C{H_3} - CH = CH - C{H_3}$
$(iii)$ $C{H_2} = CH - CH = C{H_2}$
$(iv)$ $H - C \equiv C - H$


(1) હાઈડ્રોક્સિ આલ્ડીહાઈડ
(2) કિટોન
(3) ડાયકિટોન
(4) આલ્કેનોઈક એસિડ