Now, the lowest set of locant rule is considered.
Number \(1\) is given to \(- CN\) group, \(- Br\) will be at the \(2^{\text {nd }}\) position and \(- OH\) will be at the \(5^{\text {th }}\) position.
So, the name is \(2\)-bromo-\(5\)-hydroxybenzonitrile.
$\begin{array}{*{20}{c}}
{O = CH - C{H_2} - CH - CHO} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,H - C = O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
$2-$ મિથાઇલ $-2-$ બ્યુટીનને કઈ રીતે રજૂ કરવામાં આવશે?
$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C{H_2}C = CH - CHC{H_2}C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}C{H_2} - CH - C{H_2}C{H_2}C{H_2}C{H_3}}
\end{array}$