Volume \(=(\text { side })^3\)

\(v=(a)^3\)

So \(\frac{\Delta V}{V}=\frac{3 \Delta a}{a}\)  \(\left\{\operatorname{given} \frac{\Delta a}{a}=-2 \%\right\}\)

\(\therefore \frac{\Delta v}{v}=3 \times-2 \quad \text { Side decreases solve used (-)ve sign }\)

\(=-6 \%\)

We know

\(\frac{\Delta v}{v}=-\frac{P}{B}\)

Substituting value of \(\Delta v / v\)

\(-\frac{6}{100}=-\frac{P}{B}\)

So bulk strain produced is \(0.06\)