At BCGF (electric field) \(\Rightarrow \overrightarrow{\mathrm{E}}=12 \hat{\mathrm{i}}-\left(\mathrm{y}^{2}+1\right) \hat{\mathrm{j}}\)
\((x=3 m)\)
Flux \(\phi_{\mathrm{II}}=12 \times 4=48 \mathrm{Nm}^{2}{ / \mathrm{C}}\)
So \(\phi_{\mathrm{I}}-\phi_{\mathrm{II}}=0-48=-48 \mathrm{Nm}^{2}{ / \mathrm{C}}\)
\(\therefore\) Correct answer \(-48\)