Diode \({D}_{1} \& {D}_{2}\) are in forward bias i.e. \({R}=30 \,\Omega\)
whereas diode \({D}_{3}\) is in reverse bias i.e. \({R}=\) infinite
\(\Rightarrow\) Equivalent circuit will be
Applying \(KVL\) starting from point \(A\)
\(-\left(\frac{{I}_{1}}{2}\right) \times 30-\left(\frac{{I}_{1}}{2}\right) \times 130-{I}_{1} \times 20+200=0\)
\(\Rightarrow-100 {I}_{1}+200=0\)
\({I}_{1}=2\)
$A$ |
$B$ |
$Y$ |
$1$ |
$1$ |
$0$ |
$1$ |
$0$ |
$0$ |
$0$ |
$1$ |
$0$ |
$0$ |
$0$ |
$1$ |