આપેલ,

$(A)$ $2 CO ( g )+ O _2( g ) \rightarrow 2 CO _2( g ) \quad \Delta H _1^\theta=- x\,kJ\,mol { }^{-1}$

$(B)$ $C$ (graphite) $+ O _2$ (g) $\rightarrow CO _2$ (g) $\Delta H _2^\theta=- y\,kJ\,mol -1$

$C$(ગ્રેફાઈટ) $+$ $\frac{1}{2} O _2( g ) \rightarrow CO ( g )$ પ્રક્રિયા માટે $\Delta H ^\theta$ શોધો.

Question

આપેલ,

$(A)$ $2 CO ( g )+ O _2( g ) \rightarrow 2 CO _2( g ) \quad \Delta H _1^\theta=- x\,kJ\,mol { }^{-1}$

$(B)$ $C$ (graphite) $+ O _2$ (g) $\rightarrow CO _2$ (g) $\Delta H _2^\theta=- y\,kJ\,mol -1$

$C$(ગ્રેફાઈટ) $+$ $\frac{1}{2} O _2( g ) \rightarrow CO ( g )$ પ્રક્રિયા માટે $\Delta H ^\theta$ શોધો.

JEE MAIN 2023, Medium

Download our app for free and get started

Solution

a
Target equation

$C \text { (graphite) }+\frac{1}{2} O _{2( g )} \rightarrow CO _{( g )} \ldots \text {.(i) } \Delta H$

$C \left(\text { graphite) }+ O _{2( g )} \rightarrow CO _{2( g )} \text {.(ii) } \Delta H _1=- y\,kJ / mole \right.$

$CO _{2( g )} \rightarrow CO _{( g )}+\frac{1}{2} O _{2( g )} \ldots \text { (iii) } \Delta H _2=\frac{ x }{2}\,kJ / mole$

$\text { eq. (i) }=\text { eq.(ii) }+ \text { eq (iii) }$

$\therefore \Delta H =\frac{ x }{2}- y =\frac{ x -2 y }{2}$

Download our app
and get started for free