For exothermic reaction, $\Delta \mathrm{H}= -ve$ i.e. heat is evolved. The temperature $\mathrm{T}_{2}$ is higher than $\mathrm{T}_{1}$
Thus, $\left(\frac{1}{T_{2}}-\frac{1}{T_{1}}\right)$ is negative.
so, $\log K_{p}^{\prime}-\log K_{p}=-$ ve or $\log K_{p}>\log K_{p}^{\prime}$
$ K_{p}>K_{p}$